Energy Distribution among Reaction Products. VII. H + F2

Abstract
The reaction H+F2HF+F has been studied by means of the ``arrested relaxation'' variant of the infrared chemiluminescence technique. Detailed rate constants k (V′, R′, T′), where V′, R′, and T′ symbolize the vibrational, rotational, and translational energies in the reaction products, are reported in the form of a contour plot. The total detailed rate constants into specified vibrational quantum states for H+F2 (summed over the rotational levels of each v′ level) are k (v′ = 1) = 0.12, k (v′ = 2) = 0.13, k (v′ = 3) = 0.25, k (v′ = 4) = 0.35, k (v′ = 5) = 0.78, [k (v′ = 6) = 1.00], k (v′ = 7) = 0.40, k (v′ = 8) = 0.26, k (v′ = 9) < 0.16 (relative to the highest rate constant k(v̂′)=1.00). In common with other members of the H+X2 family of reactions (X is a halogen) the H+F2 reaction exhibits a comparatively low fractional conversion of the total available energy into internal excitation of the new molecule. The mean fractions entering vibration and rotation are V′=0.53 and R=0.03. This behavior appears to be characteristic of reactions involving substantial ``repulsive'' energy release and a light attacking atom. Evidence is presented to show that H+F2 occupies a special place in the H+X2 family in that the repulsive energy release (energy released as the products separate) is restricted to the period when the F atoms are at close range. An approximate relation log Ea∝ ρ2f[a/(1−a)], relating the activation energy Ea to the X–X bond extension at the termination of energy release, ρ2f, and the attractive energy release a, is derived and is tested for the family of reactions H+X2. There is only a very small increase in product rotational excitation with decreasing vibrational excitation. It follows that the translational energy of the products is markedly greater for successively lower v′ states.