Abstract
Methods introduced in a previous paper are used to calculate the g tensors of aromatic hydrocarbons. For even-alternant molecules made up of six-membered rings, it is predicted that the axes of the g tensor are the same for both ions, and that (gxx - gyy ) is equal in magnitude and opposite in sign for the two ions, where the z axis is perpendicular to the molecular plane. Such molecules in their lowest triplet states, and all neutral odd-alternant radicals, are predicted to have gxx = gyy = 2·0027, gzz = 2·0024.

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