Abstract
We investigate necessary and sufficient conditions under which the difference of the resolvents RzR0z of two self‐adjoint operators of the form H01F(P) and HF(P) + V(Q) is nuclear. Here F(P) denotes a positive and continuous function of the usual momentum observables P and V(Q) a function of the conjugate coordinate observables. Roughly speaking, we prove that RzR0z is nuclear if and only if F(P) increases faster than |P|3/2 at large |P| and V(Q) falls off to zero faster than 1/|Q|3 at large |Q|. (For a precise statement of this result Sec. 3.) In particular, it is noticed that if H0 = (|P|2 + m2)1/2 the relativistic free Hamiltonian, then RzR0z is not nuclear for any of the (suitably regular) potential V(QN.W.) where QN.W. denotes the usual Newton‐Wigner position operator of the relativistic particle. We also investigate in Sec. 3 the necessary and sufficient conditions for Rzβ V Rz(β>0;β≠1) to be nuclear. The implications of these results for the asymptotic behavior of the total scattering cross sections at high energy is discussed in Sec. 4.

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