Abstract
The fluorescence intensity and the yield of the NO β bands, originating from photodissociation of N2O, was measured as a function of wavelength of incident light in the vacuum ultraviolet region. Photon energies required for the occurrence of the fluorescence are far less than the threshold energy to produce NO(A2 Σ+, B 2Πr) directly from N2O, indicating that the emission is due to secondary processes. The fluorescence intensity curve follows closely the absorption curve of N2O indicating that excited species responsible for the emission are produced from dissociation of electronically excited N2O rather than from the direct dissociation to these species. A mechanism of fluorescence is discussed on the basis of the threshold energy above which a specific photochemical process is possible. Reactions responsible for the β emission in the absorption region 1400 to 1550 Å of N2O are production of N(2D) and O(1S) followed by N(2D)+N2ON2+NO(B 2Πr) and O(1S)+N2ONO+NO(B 2Πr) . In the region below 1400 Å, N(2P) and N2(B 3Πg, B3Σu) also can contribute to the emission. When NO was added to N2O, the fluorescence intensity increased considerably and the emission changed from β to γ bands. Reactions which produce the emission in the absorption region 1400 to 1550 Å are N2O lim N2(A 3Σu+)+O(3P) followed by N2(A 3Σu+)+NON2+NO(A 2Σ+) . Below 1350 Å additional excited molecules N2(B 3Πg, B3Σu) can contribute to the emission in similar reactions.

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