The lowest triplet state of Zn porphin
- 1 January 1971
- journal article
- research article
- Published by Taylor & Francis in Molecular Physics
- Vol. 22 (5), 741-751
- https://doi.org/10.1080/00268977100103061
Abstract
Phosphorescence microwave double resonance experiments are reported on Zn porphin at 1·2 K. In glassy solution very broad resonance transitions are observed. However, for Zn porphin in a crystalline n-octane matrix—a system known for its sharp optical spectra (Shpolskii effect)—three pairs of microwave transitions with widths of a few MHz are found, all of them corresponding to a decrease in phosphorescence intensity. By studying the behaviour of the signals for various methods of preparation of the sample and as a function of the optical bandwidth of excitation and detection, one pair of transitions could be assigned to monomeric solute molecules. The corresponding zero-field splittings are |X - Z| = 1355, |Y - Z| = 806 MHz. It was further established that by ‘pumping’ either of these transitions a third one can be detected at the difference frequency, so that the order of the levels must be X> Y>Z (or reverse). The results indicate that the molecule no longer possesses a four-fold axis in the excited state. What one observes must be the lowest vibronic level of a Jahn-Teller unstable state, the degeneracy of which is removed by an anisotropic crystal field. From some preliminary E.S.R. experiments on zinc porphin in an EPA glass at 77K it is concluded that Z corresponds to that component where the angular momentum lies in the molecular plane; for a ππ* electronic state this is expected to be the lowest in energy of the three.Keywords
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