Abstract
The equilibrium, TiO2(rutile)+4HCl=TiCl4(g)+2H2O(g), was studied in the temperature range of 800—1400°K by means of a flow method in which HCl was passed over a sample of rutile. The heat of reaction was found to be 12.9 kcal/mole in this temperature range. This leads to a value of —182.9±0.5 kcal/mole for ΔHf of TiCl4(g) and —192.5±0.5 kcal/mole for ΔHf of TiCl4(l). The entropy of TiCl4(g) at 1100°K is found to be 124 cal/°/mole.

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