NMR Spectrum of the Ethyl Group. An Exact Solution

Abstract

An exact solution of the spin Hamiltonian for the ethyl group has been calculated and the results have been compared with the experimental NMR spectra of ethyl sulfide and tetraethylsilane. For ethyl sulfide it was found that δH₀=52.8±0.4 cycles at 40 Mc and J=7.42±0.05 cycles. For tetraethylsilane, δH₀=—16.9±0.4 cycles at 40 Mc and J=7.9±0.2 cycles.