Abstract
The complex [Ru2Cl3(Et2PhP)6]+Cl abstracts a carbonyl group from saturated aldehydes to give RuCl2(CO)(Et2PhP)3. With acetaldehyde the other product is methane. With propanol and butanal the hydrocarbons formed comprise the alkane and the alkane derived from the alkyl chain: the alcohol corresponding to the aldehyde is also observed as a reaction product. This system differs from the decarbonylation of aldehydes by RhCl(Ph3P)3 in which, under similar conditions, the hydrocarbon formed is predominantly the alkane. The difference is further illustrated by the reactions of the ruthenium and rhodium complexes with the deuteriated aldehydes C2H5CDO and CD3CH2CHO. Whereas the rhodium complex leads to C2H5D and CD3CH3 respectively, supporting published evidence of an intramolecular transfer (with respect to one molecule of aldehyde) of the aldehydic hydrogen to the alkyl group, the ruthenium system gives rise to a variety of deuteriated hydrocarbons showing labilisation of both α-and β-hydrogen atoms. No evidence for free-radical participation has been obtained for the ruthenium system, for which possible reaction mechanisms are discussed: participation of a 3π-ketyl system provides an attractive rationalisation of the exchange observations.