Abstract
A relation between the two-particle forward scattering amplitude, fk(0), and the volume integral over the optical potential, Vk(x), is given in the high-energy limit, which is valid at least to second order in the two-body interactions, neglecting correlation and exchange terms. The relation is Vk(x)dx=(2π2m)Afk(0), Where A is the number of nucleons in the target, and m is the reduced mass of the two-particle system. The connection between the shape of the optical-model potential and the density distribution of the target nucleus is discussed.